Excluding pattern from regex

[TheVig]

1. this is text with //a comment

2. this is text with a link http://example.com


Looking for the to correct regular expression to remove from "//" to the end of the line in #1 but not remove "//" to the end of the line in #2

Thanks,
Jim

Edit:

Code:

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s.replacerx("(?<!http:)//.*\r\n")

[Kevin]

if just need single replacement use flag 4
Function Function185

Code:

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s.replacerx("//" "" 4)

or
Function Function185

Code:

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str s=
;this is text with //a comment
;blah
;blah
;this is text with a link http://example.com
;this is text with //a comment also
;this is text with a link also http://www.example.com
s.replacerx("(?<!http:)//")
out s

[TheVig]

This is to remove comments from javascript. Need multiple replacements. Figured the syntax out for not preceded by (?<!http

[TheVig]

Code:

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s.replacerx("(?<!:)//.*\r\n")